Dyskusje Q&A

String s1 = new String ("Hi"); String s2 = new String("Hi"); Why s1 == s2 returns false ??

0 głosów

14th Sep 2017, 9:34 AM

Divya Vishwakarma

What is the difference between 1. String s1 = new String ("abc"); 2. String s1 = "abc"; ?

constructors string

1 Głos

15th Mar 2019, 5:28 PM

Soma Venkata Sai Krishna

String s1 == string s2 produce the output as false while we assuming the same string in both s1 and s2..

2 głosów

23rd Sep 2018, 8:13 AM

M.MANIVANNAN

s1 =[3,4] s2 =[1,2] s3=list() i=0 j=0 for i in s1: for j in s2: s3.append((i,j))

for loops nested

-4 głosów

31st May 2020, 7:10 PM

SAADAT ALI

s = input() def hashtagGen(text): s1 = s.replace(" " , "") return "#"+s1 print(hashtagGen(s))

1 Głos

22nd Jun 2022, 2:12 PM

Raj Jaiswal185

I have this program and it’s telling me theres a problem with the last s1

1 Głos

1st Mar 2018, 3:22 PM

Camila Lancheros

s="hello" s1="elloh" if s1 in s+s: print("True") else: print("Fasle") How to implement this in Linked List ?

linkedlist lists python python3

1 Głos

11th Feb 2022, 11:11 AM

Manoj Bhaagam

struct student { int age; int grade; char name[40]; }; int main() { struct student s1 ={ .age = 18,.grade = 7

0 głosów

27th Sep 2021, 6:26 AM

Gulafsha Syed

Не совсем понимаю что здесь написано reversed = names.sort( { s1, s2 in return s1 > s2 } )

1 Głos

4th Oct 2017, 8:39 PM

Yevhen Morkovin

intersect(s1, s2) where s1 and s2 are lists representing sets, computes and return a list representing the intersection of the t

0 głosów

19th Sep 2016, 2:37 PM

Vinh Le

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