I’m trying to print out the pets in the first position in the list, i didnt get error but i cant print them out

Question

https://code.sololearn.com/c1PBlh8mYYRg/?ref=app

Answer 1

Jay Matthews Following your logic i even tried to look for a matching as the first pet in the petlist, in ownerlist.
for a in ownerlist:
if a.pets == petlist[0]:
print(”found)”)
Something wrong with it?

Answer 2

Jay Matthews ok nice, i’m trying to find which owner has a certain pet, so when i get a match i would print(a.name,a.lastname)
Instead of ”found”
Atleast thats how i’m thinking

Answer 3

Jay Matthews u mean aside from typeofpet, name, gender and age? That would mean the pets had already owners from beginning and it wasnt assigned to them

Answer 4

When i’m making a pet and putting it in the petlist i have to declare an owner also otherwise i will get an error.
Petx= cat(”cat”, ”catname”, ”male”, 4)
This would then cause an error because i didnt give the pet an owner

Answer 5

protector table
https://ptpads.com/
Hey, I get what you’re trying to do with printing the first pets in the list. Sometimes the issue is just how you’re accessing them—make sure you’re calling the right index. Also, if you’re using a protector table, check that it’s not blocking the data output. Once that’s fixed, it should print fine.