- 5
bruh
Fill in the blanks to define a function that prints "Yes", if its parameter is an even number, and "No" otherwise. even(x): if x%2 == 0: ("Yes") print("No")
1 Antwoord
- 3
plz help me
Heb je vaak vragen zoals deze?
Leer efficiënter, gratis:
Fill in the blanks to define a function that prints "Yes", if its parameter is an even number, and "No" otherwise. even(x): if x%2 == 0: ("Yes") print("No")
Leer efficiënter, gratis:
