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Transform in c++

Transform this in c++ format x(y) = 1/4 * ( y^2 - ln y^2 - 1)

c#pythonc++javamathformulapy
30th Apr 2020, 5:28 PM
Mell Note
Mell Note - avatar
1 Risposta
+ 5
#include <cmath> double x(int y) { return 1/4*(pow(y,2)-log(pow(y, 2))-1); }
30th Apr 2020, 5:35 PM
minirkk
minirkk - avatar

Hai spesso domande come questa?

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