F&A Diskussionen
x = 1
while x < 10:
if x%2 == 0:
print(str(x) + " is even")
else:
print(str(x) + " is odd")
elif:
3 Stimmen
7 Antworten
Hi everyone, why is it getting 25 as an output in this code? Isn't it "a < 25" after all?
1 Stimme
3 Antworten
can someone help, fill in the blanks to print all elements of the array using a for loop?
int [] arr= new int [7];
? (int k=0; k < ? ; k++){
console.writeline ( ??? [ k] );
-1 Stimme
7 Antworten
weight = flaot(input())
height = flaot(input())
bmi = weight/(height**2)
if bmi < 18.5:
print('underweight')
elif (bmi >= 1
-1 Stimme
3 Antworten
# python
i = 0
while i < 10:
print("hallo")
i += 1
Brother and sister help this programming error
1 Stimme
3 Antworten
#include<iostream>
using namespace std;
void f(int n)
{
if (n == 1 || n == 0)
return;
else
{
cout <
0 Stimmen
5 Antworten
What is meta charset?
1 Stimme
2 Antworten
why cant we use <> in switch statements like switch (age){ case < 16}, why we cant use <?
1 Stimme
4 Antworten
i know about #include <stdio.h> header file ,is we can replace with <iostream> header file with < stdio.h > ??
0 Stimmen
4 Antworten
You are given an arrayย A1,A2...AN. You have to tell how many pairsย (i, j)ย exist such thatย 1 โค i < j โค Nย andย Aiย XORย Ajย isย odd.
6 Stimmen
2 Antworten
Why dont my cpp code works when i use < conio.h> or <graphics.h>?? Pls help. No such file or directory is seen in output section
2 Stimmen
7 Antworten
any competitions present?
0 Stimmen
2 Antworten
What is the output of this code? for(var x =0; x==x; x++) { if(x > 5 && x < 8) { document.write(x); break;} }
5 Stimmen
5 Antworten
weight = input()
height = input()
BMI = weight / (height ** 2)
if BMI < 18.5:
print(Underweight)
elif BMI >= 18.5 and BM
2 Stimmen
4 Antworten
Why in HTML, there are always the < > part and <\> part? I dont understand. What if I delete the <\> part?
4 Stimmen
3 Antworten
What is the difference between < href> and <src> how can i use my picture in my blog ??? Tell me the code
1 Stimme
6 Antworten
x = 1
while x < 10:
if x%2 == 0:
print(str(x) + "hallo")
else:
print(str(x) + "world")
x += 1
2 Stimmen
2 AntwortenCan we like type if statement with 2 condition. For example - if (int > 60) ( int < 70 )
1 Stimme
4 Antworten
I am getting an error : bad operand types for binary operator '<' if ( x < 18) { first type: "Scanner" , second type : "int"
0 Stimmen
7 Antworten
what is the meaning of this return, (arr[0] < arr[1] && restArray), plz explain the process of excuting
0 Stimmen
1 Antwort
How strings are compares in python like is ab greater than z or abc less than p or b < d . How to know this?
0 Stimmen
6 Antworten
#include <iostream>
using namespace std;
int main()
{
int num = 1;
while (num < 7) {
cout << "Number: " << num
0 Stimmen
3 Antworten
Why is the output of this code also 5? Isn't the if num < 5: an inner statement of the if num> 3 ?
0 Stimmen
4 Antworten
How does >>> print( 'True' < "true") evaluate to result as True in Python? does Python consider the ASCII value for comparison?
3 Stimmen
2 Antworten
Why can't I add a picture ?
0 Stimmen
11 Antworten
Can anyone please explain me object pointing methods (pointer and others) and about " ::" < these dots and CONSTANT ..??
3 Stimmen
1 Antwort
public class whileLoop {
public static void main(String[ ] args) {
int a = 10;
while(a < 20);
System
0 Stimmen
2 Antworten
Please tell me the meaning of voteable = ( age < 18) ? , and what is the meaning of ? (question mark) here ????????
1 Stimme
6 Antworten
I want the result to be 6(or < 9), because that is the condition ( srry google traslate) im a beginner
1 Stimme
2 Antworten
D={'Ahmed':[1,5,3], 'Ali':[6,2,4]}
for item in D:
count = len(D[item]) - 1
x = 0
while x < count:
D[item][count] += 1
0 Stimmen
1 Antwort
#include <iostream>
using namespace std;
void test(int*, int*);
int main() {
int a = 5, b = 5;
cout << "Before changing:" <
-1 Stimme
2 Antworten
Heute heiร
Need suggestions
0 Votes
Best code for creating games?
0 Votes
progaming
1 Votes
Java full stack
0 Votes
Calculator
0 Votes
Anyone Learning Godot?
1 Votes
Duration of heart refilling
0 Votes